WebPublisher/JavaScript & jQuery
[javaScript] data set 활용해 jquery 없이 탭메뉴 만들기
amanda
2025. 6. 23. 14:04
<div class="tab_wrap">
<!-- tab menu -->
<ul class="tabs">
<li class="tab_item active"><a href="#n" class="tab_link" data-tab="tabCnt01"></a></li>
<li class="tab_item"><a href="#n" class="tab_link" data-tab="tabCnt02"></a></li>
</ul>
<!-- tab contents -->
<div class="tab_cnt active" data-order="tabCnt01">
</div>
<div class="tab_cnt" data-order="tabCnt02">
</div>
</div>
.tab_cnt{display: none;}
.tab_cnt.active{display: block;}
const tabMenu = document.querySelectorAll('.tabs li');
const tabBtn = document.querySelectorAll('.tab_link')
const tabCont = document.querySelectorAll('.tab_cnt');
tabBtn.forEach(function(e){
e.addEventListener('click', () => {
const dataTab = e.dataset.tab;
tabMenu.forEach(function(i){
i.classList.remove('active');
});
e.parentNode.classList.add('active');
tabCont.forEach(function(item){
let dataOrder = item.dataset.order;
if(item.dataset.order === dataTab){
item.classList.add('active');
}else{
item.classList.remove('active');
}
})
})
})
참고